Cara mencari dan hasil dari √192 :√6
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Jawaban:
Bentuk Akar
[tex] \sqrt{192} \div \sqrt{6} [/tex]
[tex] = \sqrt{192 \div 6} [/tex]
[tex] = \sqrt{32} [/tex]
[tex] = \sqrt{16 \times 2} [/tex]
[tex] = \sqrt{16} \times \sqrt{2} [/tex]
[tex] = \sqrt{ {4}^{2} } \times \sqrt{2} [/tex]
[tex] = 4 \times \sqrt{2} [/tex]
[tex] = 4 \sqrt{2} [/tex]
[answer.2.content]
